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CGP EDU Academic Team
Published on: September 12, 2026
A Carnot’s engine is made to work between 200°C and 0°C first and then between 0°C and –200°C. The ratio of efficiencies of the engine in the two cases is
Text Solution
Verified by ExpertsThe correct answer is:
B
In first case $\eta_1 = 1 - \frac{T_2}{T_1} = 1 - \frac{(273+0)}{(273+200)} = \frac{200}{473}$ In second case $\eta_2 = 1 - \frac{(273-200)}{(273+0)} = \frac{200}{273}$ $\Rightarrow \frac{\eta_1}{\eta_2} = \frac{1}{\left(\frac{473}{273}\right)} = 1 : 1.73$
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